Topic 1 · pp. 16–18 · Free
Topic Notes · Easy summaries with diagrams
Chapter 15 — Chapter 15 — Stoichiometry
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📘Easy summary
At RTP (25 °C, 1 atm) one mole of any gas occupies 24 dm³ (molar volume) — follows from Avogadro's law (equal volumes contain equal numbers of molecules). Moles of gas = volume (dm³) / 24. Useful to find volumes of gases produced or used in reactions without weighing them.
⭐Key points
- 1 mol = 6.02 × 10²³ particles.
🔬Diagram
🌿Real-life example
15 mol NH₃ = 360 dm³.
💡Exam tip
- Use 24 dm³ (RTP), not 22.4.
✅Quick check
1. 18 dm³ CH₄ = ? mol
2. Molar volume RTP:
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